x^2+2x+(1/16)=0

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Solution for x^2+2x+(1/16)=0 equation: 


x in (-oo:+oo)

x^2+2*x+1/16 = 0

x^2+2*x+1/16 = 0

DELTA = 2^2-(1/16*1*4)

DELTA = 15/4

DELTA > 0

x = ((15/4)^(1/2)-2)/(1*2) or x = (-(15/4)^(1/2)-2)/(1*2)

x = ((15/4)^(1/2)-2)/2 or x = (-((15/4)^(1/2)+2))/2

x in { (-((15/4)^(1/2)+2))/2, ((15/4)^(1/2)-2)/2 }

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